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BFS+位运算+回溯路径,G++500MS#include<iostream>
#include<cstdio>
#include<cstring>
#include<queue>
using namespace std;
#define N 5
int sd,key=0;
int vis[1<<16];
int dir[16] = {4383,8751,17487,34959,4593,8946,17652,35064,7953,12066,
20292,36744,61713,61986,62532,63624};
struct node
{
int sum,num,step;
}cur;
struct path
{
int x,pre;
}p[100001];
void f(int index)
{
if(index)
{
f(p[index].pre);
printf("%d %d\n",p[index].x/4+1,p[index].x%4+1);
}
}
void bfs()
{
int i,j,k;
cur.sum=sd;
cur.num=0;
cur.step=0;
p[1].pre=0;
queue<node>q;
q.push(cur);
while(!q.empty())
{
node b=q.front();
q.pop();
if(b.sum==0)
{
printf("%d\n",b.step);
f(b.num);
return;
}
for(i=0;i<16;i++)
{
node a=b;
a.sum^=dir[i];
if(!vis[a.sum])
{
a.num=++key;
a.step++;
p[key].pre=b.num;
p[key].x=i;
q.push(a);
vis[a.sum]=1;
}
}
}
}
int main()
{
int i,j;
char s[5];
for(i=0;i<4;i++)
{
scanf("%s",s);
for(j=0;j<4;j++)
{
if(s[j]=='+')
{
sd+=(1<<i*4+j);
}
}
}
bfs();
return 0;
}
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