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Re:你自己试一下一些极端的数据吧,例如边界值什么的In Reply To:你自己试一下一些极端的数据吧,例如边界值什么的 Posted by:frkstyc at 2005-05-23 17:53:40 我试了。您看我的程序:
//******************************************************************
//********* *********
//********* *********
//wangping
//
//******************************************************************
#include<iostream>
#include<iomanip>
#include<algorithm>
#include<fstream>
#include<sstream>
#include<cstdlib>
#include<cstdio>
#include<cmath>
#include<string>
using namespace std;
int main(){
int d,L,p,i;
double eps=1.0;
double A,D,P;
cin>>A>>L;
if(fabs(A-1.0)<1e-12){cout<<"1 1\n";return 0;}
if(fabs(A-2.0)<1e-12){cout<<"2 1\n";return 0;}
if(fabs(A-3.0)<1e-12){cout<<"3 1\n";return 0;}
if(fabs(A-4.0)<1e-12){cout<<"4 1\n";return 0;}
if(fabs(A-5.0)<1e-12){cout<<"5 1\n";return 0;}
if(fabs(A-6.0)<1e-12){cout<<"6 1\n";return 0;}
if(fabs(A-7.0)<1e-12){cout<<"7 1\n";return 0;}
if(fabs(A-8.0)<1e-12){cout<<"8 1\n";return 0;}
if(fabs(A-9.0)<1e-12){cout<<"9 1\n";return 0;}
if(fabs(A-10.0)<1e-12){cout<<"10 1\n";return 0;}
if(fabs(A)<1e-12){cout<<"0 1\n";return 0;}
for(i=1;i<=L;i++){
D=i;
P=floor(D*A+0.5);if(P<=L){
//if((P<L)&&(abs(P/D-A)<eps)){eps=abs(P/D-A);d=i;p=floor(D*A+0.5);}
if((fabs(P/D-A)<eps)){
eps=fabs(P/D-A);
d=i;p=floor(D*A+0.5);}
//cout<<(P/D-A)<<'\t'<<setw(10)<<eps<<'\t'<<A<<endl;
}
}
cout<<p<<" "<<d<<endl;
return 0;
}
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