i*(i+1)/2<t

附代码c++

#include <stdio.h>
int main()
{
    long long num,cas,t,n,a,cnt;
    scanf("%I64d",&t);
    while(t--)
     {
         scanf("%I64d%I64d",&cas,&num);
         cnt=0;num*=2;
         for(n=2;n*n<num;n++)
          if(num%n==0)
           {
               a=(num/n)-n+1;
               if(a%2==0)cnt++;
           }
         printf("%I64d %I64d\n",cas,cnt);
     }
}