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水水更健康,贴个码#include <stdio.h> #include <math.h> #include <algorithm> #include <map> #include <string> #include <string.h> #include <queue> #include <set> using namespace std; int p[26]; int colors[26][100]; pair<int,int> block[200]; int dp[200][200]; pair<int,int> mid[100][2][20]; int mid_sz[100][2]; void inline Add_mid0(int idx,int cnt,int cost) { for(int i=0;i<mid_sz[idx][0];i++) { if(mid[idx][0][i].first<=cnt) { if(cost-cnt>=mid[idx][0][i].second-mid[idx][0][i].first) return; } else if(cost-cnt<=mid[idx][0][i].second-mid[idx][0][i].first) {swap(mid[idx][0][i],mid[idx][0][--mid_sz[idx][0]]); i--;} } mid[idx][0][mid_sz[idx][0]++]=make_pair(cnt,cost); } void inline Add_mid1(int idx,int cnt,int cost) { for(int i=0;i<mid_sz[idx][1];i++) { if(mid[idx][1][i].first<=cnt) { if(cost>=mid[idx][1][i].second) return; } else if(mid[idx][1][i].second>=cost) {swap(mid[idx][1][i],mid[idx][1][--mid_sz[idx][1]]); i--;} } mid[idx][1][mid_sz[idx][1]++]=make_pair(cnt,cost); } int main() { int m,n; char c,pre; while(scanf("%d",&m)!=EOF) { n=0; memset(p,0,26<<2); while((pre=getchar())&&!isupper(pre)); while(1) { block[n]=make_pair(pre-'A',p[pre-'A']); dp[n][n]=1; while((c=getchar())&&c==pre) dp[n][n]++; if(dp[n][n]>=m) dp[n][n]=1; else dp[n][n]=m-dp[n][n]; colors[pre-'A'][p[pre-'A']++]=n++; if(!isupper(c)) break; pre=c; } for(int i=1;i<n;i++) { for(int j=0;j<i;j++) dp[j][i]=dp[j][i-1]+dp[i][i]; int ci=block[i].second; mid[ci][0][0]=make_pair(m-dp[i][i],0); mid_sz[ci][0]=1; mid_sz[ci][1]=0; for(int cj=ci-1,j;cj>=0;cj--) { j=colors[block[i].first][cj]; mid_sz[cj][0]=mid_sz[cj][1]=0; for(int ck=ci,k;ck>cj;ck--) { k=colors[block[i].first][ck]; for(int i_mid=0;i_mid<mid_sz[ck][0];i_mid++) { int cost=dp[j+1][k-1]+mid[ck][0][i_mid].second; if(cost>=dp[j][i]) continue; if(dp[j][j]>mid[ck][0][i_mid].first) { Add_mid0(cj,m-dp[j][j]+mid[ck][0][i_mid].first,cost); dp[j][i]=min(dp[j][i],cost+dp[j][j]-mid[ck][0][i_mid].first); } else { Add_mid1(cj,m-dp[j][j],cost); dp[j][i]=cost; } } for(int i_mid=0;i_mid<mid_sz[ck][1];i_mid++) { int cost=dp[j+1][k-1]+mid[ck][1][i_mid].second; if(cost>=dp[j][i]) continue; if(dp[j][j]>mid[ck][1][i_mid].first) { Add_mid1(cj,m-dp[j][j]+mid[ck][1][i_mid].first,cost); dp[j][i]=cost; } } } for(int k=j-1;k>=0;k--) dp[k][i]=min(dp[k][i],dp[k][j-1]+dp[j][i]); } } printf("%d\n",dp[0][n-1]); } } Followed by: Post your reply here: |
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