| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
对角线,注意n=1,e=1的情况就OK#include <cstdio>
int main()
{
int n,e;
while(scanf("%d%d",&n,&e)!=EOF)
{
long long l=0,w=0,t;
for (int i=1;i!=n;++i)
{
scanf("%lld",&t);
l+=t;
}
for (int i=1;i!=e;++i)
{
scanf("%lld",&t);
w+=t;
}
long long ans=0;
while(ans*ans<l*l+w*w)++ans;
printf("%lld\n",ans);
}
return 0;
}
当n=1,e=1的时候直接输出ans=0就ok了,这里wa了,⊙﹏⊙b汗
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator