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Re:位运算+一个floyd。没什么效率但是很简单In Reply To:位运算+一个floyd。没什么效率但是很简单 Posted by:Mcfaddan_b at 2008-03-23 18:38:46 > 用2进制表示26个字母。矩阵初始1，建图的时候用或运算。 > floyd的时候用与和或运算。 > 到时候只要读矩阵中的数，依次移位只要是1就输出相应的字母就OK了。 > 突然想到的这个很好玩的方法~呵呵 Followed by:
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