| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
其实可以把每个字符串当成2个字符串输入然后用25减去它们的长度求出空格数。。。#include<iostream>
#include<string>
using namespace std;
int main()
{
string str1,str2;
int line;//每次计算的行数
int min;//空格最少行所含空格数
int space[100];//各行空格数
int answer;//题目答案
int i,j;//计数器
while(cin>>line&&line!=0)
{
min=25;
answer=0;
for(i=0;i<line;i++)
{
cin>>str1;
if(str1.length()<25)
{
cin>>str2;
space[i]=25-str1.length()
-str2.length();
}
else space[i]=25-str1.length();
if(min>space[i])
min=space[i];
}
for(j=0;j<line;j++)
answer=answer+space[j]-min;
cout<<answer<<endl;
}
return(0);
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator