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同问

Posted by frkstyc at 2005-05-21 19:51:43 on Problem 1809
In Reply To:求救:怎么会WA呢 Posted by:seol at 2004-10-03 22:19:23
> #include <stdio.h>
> #include <stdlib.h>
> 
> struct  Node;					  /* 单链表结点类型 */
> typedef  struct Node  *PNode;	  /* 结点指针类型 */
> typedef  struct Node  *LinkList;  /* 单链表类型 */
> 
> struct  Node { 					  /* 单链表结点结构 */
>     long int info;
>     PNode     link;
> };
> 
> LinkList  createNullList_link( void ) {   
>     LinkList llist;
>     llist = (LinkList)malloc( sizeof( struct Node ) );	/* 申请表头结点空间 */
>     if( llist != NULL ) llist->link = NULL;
>     return llist;
> }
> 
> long int count1(long int c)
> {
> 	if (c==0 || c==1 || c==2) return 0;
> 	return (c*(c-1)*(c-2)/6);
> }
> 
> long int count2(long int c1, long int c2)
> {
> 	if (c1==0) return 0;
> 	return (c2*c1*(c1-1)/2);
> }
> 
> LinkList create(LinkList llist)
> {
> 	PNode p=llist,q;
> 	long int num,i;
> 	long int number,j,x,y,mm,b1,b2,b3,b4;
> 	scanf("%ld",&num);
> 	for (i=0;i<num;i++) {
> 		scanf("%ld",&number);
> 		b1=b2=b3=b4=0;
> 		for (j=0;j<number;j++) {
> 			scanf("%ld %ld",&x,&y); if (x<0) x=-x; if (y<0) y=-y;
> 			if (x%2==0 && y%2==0) b1+=1;
> 			if (x%2==0 && y%2==1) b2+=1;
> 			if (x%2==1 && y%2==0) b3+=1;
> 			if (x%2==1 && y%2==1) b4+=1;
> 		}  
> 		mm=count1(b1)+count1(b2)+count1(b3)+count1(b4);
> 		mm+=count2(b1,b2)+count2(b1,b3)+count2(b1,b4)+count2(b2,b1)+count2(b2,b3)+count2(b2,b4)+count2(b3,b1)+count2(b3,b2)+count2(b3,b4)+count2(b4,b1)+count2(b4,b2)+count2(b4,b3);
> 		q=(PNode)malloc(sizeof(struct Node));
> 		if (q==NULL)  {printf("Out of space!");return NULL;}
> 		q->info=mm; q->link=NULL;p->link=q;p=p->link;
> 	}
> 	return llist;
> }
> 
> void print(LinkList llist)  /* 打印 */
> {
> 	long int s=1;
> 	PNode p=llist->link;
> 	while (p!=NULL) {
> 		printf("Scenario #%ld:\n",s);
> 		printf("%ld\n\n",p->info);
> 		s++;
> 		p=p->link;
> 	}
> }
> 
> int main()
> {
> 	LinkList llist;
> 	llist=createNullList_link();
> 	llist=create(llist);
> 	print(llist);
> 	return 0;
> }

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