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开始一直想不通，看如下话语后顿悟！堆中元素个数now[i]、这些数的和s[i]、属于这个堆但被从堆中去掉的元素个数go[i]、这些数的和b[i] 最后ans=sigma每个块(该块中位数*now[i]-s[i]+b[i]-go[i]*中位数) Followed by: Post your reply here: |
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