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Re:其实这道题可以用这个公式In Reply To:其实这道题可以用这个公式 Posted by:slp at 2010-09-14 22:34:35 > 其实这道题可以用这个公式 > tmp = sum( log10(i) ) 0<i<=n > len(n!)=(int)(tmp)+1 > 打表即可过了... 500ms > 公式的证明我还不会,求证明: 为什么我的超时? #include<iostream> #include<cmath> using namespace std; int main() { int n,i,t; double d; cin>>t; for(int a=0;a<t;a++) { cin>>n; d=0; for(i=1;i<=n;i++) d+=log10((double)i); cout<<(int)d+1<<endl; } //system("pause"); return 0; } Followed by:
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