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Re:大神指点下为什么这个代码会超过时间限制In Reply To:大神指点下为什么这个代码会超过时间限制 Posted by:1120112227 at 2012-05-10 17:07:39 > #include <stdio.h>
> #include <iostream>
>
> using namespace std;
>
> int main()
> {
> static int cases,Arraynum,Array[10000];
> int i,j,k,Flag;
> static int mark,MaxL[10000],MaxR[10000],ans,neg;
> cin>>cases;
> while(cases==0)
> {
> cin>>Arraynum;
> for(i=0;i<Arraynum;i++)
> cin>>Array[i];
> for(mark=0;mark<Arraynum;mark++) //该数字前后的子数组最大值
> {
> for(i=Flag=neg=0;i<=mark;i++) //包含mark
> {
> if(Array[i]>0&&Flag==0)
> {
> Flag=1;
> MaxL[mark]+=Array[i];
> continue;
> }
> if(Array[i]>0&&Flag==1)
> {
> if(neg+Array[i]>=0)
> {
> MaxL[mark]+=(neg+Array[i]);
> neg=0;
> }
> continue;
> }
> if(Array[i]<=0&&Flag==1) neg+=Array[i];
> }
> for(j=Arraynum-1,Flag=neg=0;j>mark;j--) //不包含mark
> {
> if(Array[j]>0&&Flag==0)
> {
> Flag=1;
> MaxR[mark]+=Array[j];
> continue;
> }
> if(Array[j]>0&&Flag==1)
> {
> if(neg+Array[j]>=0)
> {
> MaxR[mark]+=(neg+Array[j]);
> neg=0;
> }
> continue;
> }
> if(Array[j]<=0&&Flag==1) neg+=Array[j];
> }
> }
> for(mark=0;mark<Arraynum;mark++)
> if(MaxL[mark]+MaxR[mark]>ans) ans=MaxL[mark]+MaxR[mark];
> printf("%d\n",ans);
> }
> return 0;
> }
不是o(n)的貌似都是超时的……
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