| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
推不出数学公式,不过觉得我的方法也不错。#include<stdio.h>
int main()
{
freopen("D:/ACMData.txt","r",stdin);
int n;
for(scanf("%d",&n);n;scanf("%d",&n))
{
int i=1;
int k;
long sum = n;
for(k = i; k<n; i++, k = (1+i)*i/2)//k为等差数列前n项和
{
sum += n-k;
}
printf("%d %ld\n",n,sum);
}
return 0;
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator