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我没仔细看,里面有一个trap是相同的词按重数算不过只输出一次

Posted by frkstyc at 2005-05-19 12:06:55 on Problem 2408
In Reply To:wa了一个上午,谁能帮我看看,是不是有什么陷阱,我是3次排序做的,每个词排一次,所有词排一次,分组后在排一次,应该是比较简单的吧 Posted by:cpp051300448324 at 2005-05-19 12:04:29
> #include<iostream>
> #include<cstring>
> #include<algorithm>
> #include<fstream>
> #define min(a,b) (a<b?a:b)
> using namespace std;
> struct tag_1{
>     char str[50];    //存储的每个词
>     char str_cmp[50];  //字典序的这个词
> };
> 
> struct tag_2{
>     tag_1 * p;   //分组的首地址
>     int size;    //分组的长度
> };  
>   
> bool cmp_1(tag_1 s1,tag_1 s2){
>     int signal=strcmp(s1.str_cmp,s2.str_cmp);
>     if(signal!=0)return signal<0;
>     else return strcmp(s1.str,s2.str)<0;
> }
> 
> bool cmp_2(tag_2 s1,tag_2 s2){
>     if(s1.size!=s2.size) return s1.size>s2.size;
>     else return strcmp((s1.p)->str,(s2.p)->str)<0;
> }        
> 
> 
> 
> tag_1 s[30000];   //单词
> tag_2 ss[30000];   //分组
> 
> int main(){
>     ifstream cin("tmp.txt");
>     int i=0,j;
>     int N;
>     while(cin>>s[i].str){
>         strcpy(s[i].str_cmp,s[i].str);
>         sort(s[i].str_cmp,s[i].str_cmp+strlen(s[i].str_cmp));
>         i++;
>     }
>     N=i;
>     int pre=0;
>     
>     sort(s,s+N,cmp_1);
>     ss[0].p=s;
>     j=1;
>     for(i=1;i<N;i++){
>         if(strcmp(s[i].str_cmp,s[i-1].str_cmp)!=0){
>             ss[j].p=s+i;
>             ss[j-1].size=i-pre;
>             pre=i;
>             j++;
>         } 
>     } 
>     ss[j-1].size=i-pre;
>     sort(ss,ss+j,cmp_2);
>     int size=min(j,5);
>     for(i=0;i<size;i++){
>         cout<<"Group of size "<<ss[i].size<<": ";
>         for(int k=0;k<ss[i].size;k++){
>             cout<<(ss[i].p+k)->str<<' ';
>         }
>         cout<<'.'<<endl;
>     }
>     system("pause");
>     return 0;
> }            
>           
>             
>         
>     

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