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wa了一个上午,谁能帮我看看,是不是有什么陷阱,我是3次排序做的,每个词排一次,所有词排一次,分组后在排一次,应该是比较简单的吧#include<iostream>
#include<cstring>
#include<algorithm>
#include<fstream>
#define min(a,b) (a<b?a:b)
using namespace std;
struct tag_1{
char str[50]; //存储的每个词
char str_cmp[50]; //字典序的这个词
};
struct tag_2{
tag_1 * p; //分组的首地址
int size; //分组的长度
};
bool cmp_1(tag_1 s1,tag_1 s2){
int signal=strcmp(s1.str_cmp,s2.str_cmp);
if(signal!=0)return signal<0;
else return strcmp(s1.str,s2.str)<0;
}
bool cmp_2(tag_2 s1,tag_2 s2){
if(s1.size!=s2.size) return s1.size>s2.size;
else return strcmp((s1.p)->str,(s2.p)->str)<0;
}
tag_1 s[30000]; //单词
tag_2 ss[30000]; //分组
int main(){
ifstream cin("tmp.txt");
int i=0,j;
int N;
while(cin>>s[i].str){
strcpy(s[i].str_cmp,s[i].str);
sort(s[i].str_cmp,s[i].str_cmp+strlen(s[i].str_cmp));
i++;
}
N=i;
int pre=0;
sort(s,s+N,cmp_1);
ss[0].p=s;
j=1;
for(i=1;i<N;i++){
if(strcmp(s[i].str_cmp,s[i-1].str_cmp)!=0){
ss[j].p=s+i;
ss[j-1].size=i-pre;
pre=i;
j++;
}
}
ss[j-1].size=i-pre;
sort(ss,ss+j,cmp_2);
int size=min(j,5);
for(i=0;i<size;i++){
cout<<"Group of size "<<ss[i].size<<": ";
for(int k=0;k<ss[i].size;k++){
cout<<(ss[i].p+k)->str<<' ';
}
cout<<'.'<<endl;
}
system("pause");
return 0;
}
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