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wa了一个上午,谁能帮我看看,是不是有什么陷阱,我是3次排序做的,每个词排一次,所有词排一次,分组后在排一次,应该是比较简单的吧#include<iostream> #include<cstring> #include<algorithm> #include<fstream> #define min(a,b) (a<b?a:b) using namespace std; struct tag_1{ char str[50]; //存储的每个词 char str_cmp[50]; //字典序的这个词 }; struct tag_2{ tag_1 * p; //分组的首地址 int size; //分组的长度 }; bool cmp_1(tag_1 s1,tag_1 s2){ int signal=strcmp(s1.str_cmp,s2.str_cmp); if(signal!=0)return signal<0; else return strcmp(s1.str,s2.str)<0; } bool cmp_2(tag_2 s1,tag_2 s2){ if(s1.size!=s2.size) return s1.size>s2.size; else return strcmp((s1.p)->str,(s2.p)->str)<0; } tag_1 s[30000]; //单词 tag_2 ss[30000]; //分组 int main(){ ifstream cin("tmp.txt"); int i=0,j; int N; while(cin>>s[i].str){ strcpy(s[i].str_cmp,s[i].str); sort(s[i].str_cmp,s[i].str_cmp+strlen(s[i].str_cmp)); i++; } N=i; int pre=0; sort(s,s+N,cmp_1); ss[0].p=s; j=1; for(i=1;i<N;i++){ if(strcmp(s[i].str_cmp,s[i-1].str_cmp)!=0){ ss[j].p=s+i; ss[j-1].size=i-pre; pre=i; j++; } } ss[j-1].size=i-pre; sort(ss,ss+j,cmp_2); int size=min(j,5); for(i=0;i<size;i++){ cout<<"Group of size "<<ss[i].size<<": "; for(int k=0;k<ss[i].size;k++){ cout<<(ss[i].p+k)->str<<' '; } cout<<'.'<<endl; } system("pause"); return 0; } Followed by:
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