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回溯 函数递归 不模拟 都能0s呢……只是不小心贡献了一个RE,怎么前辈讨论消减时间这么激烈??#include <iostream> using namespace std; char hl[9],maze[9][9]; int n,ii; void search(const int k,const int bian) { int i,j; for (i=bian-1;i>k-2;i--) { for (j=0;j<n;j++) if (maze[i][j]=='#' && hl[j]==0) if (i && k>1) { hl[j]=1; search(k-1,i); hl[j]=0; } else ii++; } } int main() { int k,i; while(1) { cin>>n>>k; if (n==-1) break; else { memset(hl,0,sizeof(hl)); for (i=0;i<n;i++) scanf("%s",maze[i]); ii=0; search(k,n); cout<<ii<<endl; } } return 0; } Followed by: Post your reply here: |
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