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Re:高精度幂ac(c++)In Reply To:高精度幂ac(c++) Posted by:0810311106 at 2009-10-15 11:48:28 > #include"iostream" > using namespace std; > int main() > { > int n; > cin>>n; > while(n--) > { > int f,s,num=0; > int a[1000]={0},temp=0; > int i,j,len=1; > a[0]=1; > cin>>f>>s; > for(i=1;i<=f;i++) > { > for(j=0;j<len;j++) > { > a[j]=a[j]*i+temp; > temp=a[j]/10; > a[j]%=10; > } > while(temp!=0) > { > a[j]+=temp%10; > temp/=10; > j++; > } > len=j; > } > /*for(i=0;i<len;i++) > cout<<a[len-1-i]; > cout<<endl;*/ > for(i=0;i<len;i++) > if(s==a[i]) > num++; > cout<<num<<endl; > } > return 0; > } Followed by: Post your reply here: |
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