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人都写2了...WA求解#include <stdio.h> #include <string.h> int main () { char str1[1002], str2[1002]; while (gets(str1) != '\0') { int len1, len2; int a[1000]={0}, b[1000]={0}; int i; int time1[300]={0}, time2[300]={0}; int x, y; int n, m; gets(str2); //比较长度,不相等重新循环 len1 = strlen(str1); len2 = strlen(str2); if (len1 != len2) { printf("NO\n"); continue; } //转化为数字数组 for (i=0; i<len1; i++) { n = str1[i] - 'A'; time1[n] ++; m = str2[i] - 'A'; time2[m] ++; } //当取到不为0的值时,即为第一个值,第二个值 for (i=0, x=0, y=0; i<len1; i++) { if (time1[i] != 0) { a[x] = time1[i]; x ++; } if (time2[i] != 0) { b[y] = time2[i]; y ++; } } //比较出现个数,不相等重新循环 if (y != x) { printf("NO\n"); continue; } //比较出现频率 for (i=0; i<x; i++) { if (a[i] != b[i]) { printf("NO\n"); //频率不相等,跳出 break; } } if (i == x) printf("YES\n");//频率相等,重新循环 } return 0; } Followed by: Post your reply here: |
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