#include <iostream>
using namespace std;
int p, e, i, d, t, n=0;
int main()
{
    while (cin>>p>>e>>i>>d, p!=-1){
        for (n++,t=d+1; t<=d+21252; t++)
            if ((t-p)%23==0 && (t-e)%28==0 && (t-i)%33==0) break;
        printf("Case %d: the next triple peak occurs in %d days.\n", n, t-d);
    }
    return 0;
}

• Re:蛋疼的题目描述。。。直接暴力就过了…… (357) s_eine 2011-12-28 10:37:44