我是广州大学的新生，在做到1001号（贵校题库编号1008）玛雅历问题时突然想到既然Haab能转换成Tzolkin，那能不能反向转换回来呢？经过几天的奋战我解决了这个问题，又花了几个小时时间解决了代码里的所有Bug，现在发上来与各位学友分享。（我们学校的OJS不带BBS，所以就只在这里发了）
#include<iostream>
#include<string>
using namespace std;
//hmn means the name of the months in Haab.
string hmn[]={" ","pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
//tdn means the name of the days in Tzolkin.
string tdn[]={" ","imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};
int condateint(int Tzdaynum,string Tzdayname) //condateint() is used to convert a date in Tzolkin to the day's order in a Tzolkin year. 
{
	int n,tdnum,j; //tdnum means the day's order in a Tzolkin year. 
	for(j=1;j<=20;j++){if(Tzdayname==tdn[j])break;}
	while(Tzdaynum<j)Tzdaynum+=13;
	Tzdaynum-=j;
	for(n=0;n<=12;n++)
	if((n*20)%13==Tzdaynum){tdnum=n*20+j;break;}
	return tdnum;
}
int main()
{
	int n,i,Tzdaynum,Tzyear,Haabday,Haabyear,amountday;
	string Tzdayname,Haabmonth;
	cin>>n;cout<<n<<endl;
	for(i=1;i<=n;i++)
	{
		cin>>Tzdaynum>>Tzdayname>>Tzyear;
		amountday=260*Tzyear+condateint(Tzdaynum,Tzdayname);
		Haabyear=(amountday-1)/365;
		Haabmonth=hmn[((amountday-1)%365)/20+1];
		Haabday=((amountday-1)%365)%20;
		cout<<Haabday<<"."<<" "<<Haabmonth<<" "<<Haabyear<<endl;
	}
	return 0;
}

• Re:经典问题玛雅历问题里的新问题 (8) 1106100214 2011-11-16 12:44:41