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Time Limit Exceeded,求解释#include "stdio.h" #include "math.h" void main() { double a,b,temp1,temp2; int i; while(scanf("%lf %lf",&a,&b)!=EOF) { if(a>b) { temp1=a; a=b; b=temp1; } for(i=1,temp1=0,temp2=0;floor(temp1)<a&&floor(temp2)<b;i++) { temp1=i*(1+sqrt(5))/2; temp2=temp1+i; } printf("%d\n",(floor(temp1)==a&&floor(temp2)==b)?0:1); } } Followed by: Post your reply here: |
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