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为什么我得到的老是Wrong Answer,哪位大神帮我看看吧,非常感谢啊

Posted by 894788609 at 2011-11-03 16:44:24 on Problem 1008
#include<stdio.h>
int main()
{
	int day[5000],year[5000],data[5000],month0[5000]={18},i,n;
	char month[5000][5],a;
	scanf("%d",&n);
	for(i=0;i<n;i++)
		month0[i]=18;
	for(i=0;i<n;i++)
	{
		scanf("%d%c%s%d",&day[i],&a,month[i],&year[i]);
	}
	printf("%d\n",n);
	for(i=0;i<n;i++)
	{
		switch(month[i][0])
		{
		case 'c':
			switch(month[i][1])
			{
			case 'h':month0[i]=8;break;
			case 'e':month0[i]=11;break;
			case 'u':month0[i]=17;break;
			}
			break;
		case 'm':
			switch(month[i][1])
			{
			case 'o':month0[i]=7;break;
			case 'u':month0[i]=14;break;
			case 'a':month0[i]=12;break;
			}
			break;
		case 'z':
			switch(month[i][1])
			{
			case 'i':month0[i]=2;break;
			case 'o':month0[i]=3;break;
			case 'a':month0[i]=10;break;
			}
			break;
		case 'y':
			switch(month[i][1])
			{
			case 'o':month0[i]=6;break;
			case 'a':month0[i]=9;break;
			}
			break;
		case 'p':
			switch(month[i][1])
			{
			case 'o':month0[i]=0;break;
			case 'a':month0[i]=15;break;
			}
			break;
		case 'k':
			switch(month[i][1])
			{
			case 'o':month0[i]=16;break;
			case 'a':month0[i]=13;break;
			}
		case 'n':month0[i]=1;break;
		case 't':month0[i]=4;break;
		case 'x':month0[i]=5;break;
		}
		data[i]=year[i]*365+month0[i]*20+day[i]+1;
		year[i]=(data[i]-1)/260;
		data[i]=(data[i]-1)%260+1;
		day[i]=(data[i]-1)%20+1;
		switch(day[i])
		{
		case 1:printf("%d imix %d\n",((data[i]-1)%13+1),year[i]);break;
		case 2:printf("%d ik %d\n",((data[i]-1)%13+1),year[i]);break;
		case 3:printf("%d akbal %d\n",((data[i]-1)%13+1),year[i]);break;
		case 4:printf("%d kan %d\n",((data[i]-1)%13+1),year[i]);break;
		case 5:printf("%d chicchan %d\n",((data[i]-1)%13+1),year[i]);break;
		case 6:printf("%d cimi %d\n",((data[i]-1)%13+1),year[i]);break;
		case 7:printf("%d manik %d\n",((data[i]-1)%13+1),year[i]);break;
		case 8:printf("%d lamat %d\n",((data[i]-1)%13+1),year[i]);break;
		case 9:printf("%d muluk %d\n",((data[i]-1)%13+1),year[i]);break;
		case 10:printf("%d ok %d\n",((data[i]-1)%13+1),year[i]);break;
		case 11:printf("%d chuen %d\n",((data[i]-1)%13+1),year[i]);break;
		case 12:printf("%d eb %d\n",((data[i]-1)%13+1),year[i]);break;
		case 13:printf("%d ben %d\n",((data[i]-1)%13+1),year[i]);break;
		case 14:printf("%d ix %d\n",((data[i]-1)%13+1),year[i]);break;
		case 15:printf("%d mem %d\n",((data[i]-1)%13+1),year[i]);break;
		case 16:printf("%d cib %d\n",((data[i]-1)%13+1),year[i]);break;
		case 17:printf("%d caban %d\n",((data[i]-1)%13+1),year[i]);break;
		case 18:printf("%d eznab %d\n",((data[i]-1)%13+1),year[i]);break;
		case 19:printf("%d canac %d\n",((data[i]-1)%13+1),year[i]);break;
		case 20:printf("%d ahau %d\n",((data[i]-1)%13+1),year[i]);break;
		}
	}
	return 1;
}

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