#include<stdio.h>
#include<string.h>
#include<ctype.h>
int test(char* A,char *B,char *C,int sign,int x); 
int main(void)
{
	int n,i,sign=0;
	char A[3][10],B[3][10],C[3][10];//A B C  分别记录天平左侧、右侧的硬币，天平平衡状况 
	scanf("%d",&n);
	for(i=0;i<n;i++)
	{
		int j;
		for(j=0;j<3;j++)
		{
			scanf("%s",A[j]);
			scanf("%s",B[j]);
			scanf("%s",C[j]);
		}
		for(j=0;j<12;j++)//假设假币偏轻、枚举 
		{
			int k;
			for(k=0;k<3;k++)
			{
				if(test(A[k],B[k],C[k],sign,j)==0)
				break;
			}
			if(k==3)
			break;
		}
		if(j!=12)
			printf("%c is the counterfeit coin and it is light.  \n",j+65);
		else
		{
			sign=1;
			for(j=0;j<12;j++)//假设假币偏重，枚举 
			{
				int k;
				for(k=0;k<3;k++)
				{
					if(test(A[k],B[k],C[k],sign,j)==0)
					break;
				}
				if(k==3)
				break;
			}
			if(j!=12)
				printf("%c is the counterfeit coin and it is heavy.  \n",j+65);
		}
	}
}
int test(char* A,char *B,char *C,int sign,int x)//验证枚举结果是否正确的函数，正确返回1 
{
	int i=0;
	int a,b;
	a=b=0;
	while(A[i]!='\0')
	{
		if(A[i]-65==x)
		a+=sign? 2:0;//假设真币重是1，假币偏轻重为0，偏重为2 
		else
		a+=1;
		i++;
	}
	i=0;
	while(B[i]!='\0')
	{
		if(B[i]-65==x)
		b+=sign? 2:0;
		else
		b+=1;
		i++;
	}
	if((a-b>0 && C[0]== 'u') || (a-b==0 && C[0] == 'e') || (a-b<0 && C[0] == 'd'))
	return 1;
	else 
	return 0;
}