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帮我看看一下思路#include <stdio.h>
#include <conio.h>
int m,n,i,j,t,k;
int main(){
scanf("%d",&t);
for(i=0;i<t;i++)
{
m=0;
scanf("%d",&k);
for(j=k+1;j<=2*k;j++)
if((k*j)%(j-k)==0)
m++;
printf("Scenario #%d:\n",i+1);
printf("%d\n\n",m);
}
getch();
return 0;
}
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