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acm十大未解之谜有一种想死的感觉,两段代码检查了10+遍,毫无差别,但是换成下面注释里面的就A,不换就WA。谁能够解释这一神奇的现象? #include<cstdio> #include<cstring> #include<string> #include<iostream> #include<algorithm> #include<cmath> using namespace std; int n,m; int gp[14][14]; long long dp[1<<14][14][14],isv[14],isl[1<<14][14][14]; void DP() { long long tem; memset(dp,-1,sizeof(dp)); memset(isl,0,sizeof(isl)); for(int i=0;i<n;i++) for(int j=0;j<n;j++) { if(i==j||gp[i][j]==0)continue; tem=(1<<j)+(1<<i); dp[tem][i][j]=isv[i]+isv[j]+isv[i]*isv[j]; isl[tem][i][j]=1; } for(int s=0;s<(1<<n);s++) for(int i=0;i<n;i++) { if((s&(1<<i))==0)continue; for(int j=0;j<n;j++) { if(i==j||(s&(1<<j))==0||gp[i][j]==0)continue; for(int k=0;k<n;k++) { if(k==j||k==i||(s&(1<<k))==0||gp[j][k]==0)continue; int ss=s-(1<<i); if(dp[ss][j][k]==-1)continue; long long tem=isv[i]+isv[i]*isv[j]+dp[ss][j][k]; if(gp[i][k]) tem+=isv[i]*isv[j]*isv[k]; if(tem>dp[s][j][j]) { dp[s][i][j]=tem; isl[s][i][j]=isl[ss][j][k]; } else if(tem==dp[s][j][j]) isl[s][i][j]+=isl[ss][j][k]; } } } /* for(int s=0;s<(1<<n);s++) for(int i=0;i<n;i++) { if((s&(1<<i))==0)continue; for(int j=0;j<n;j++) { if(i==j||(s&(1<<j))==0||gp[i][j]==0)continue; for(int k=0;k<n;k++) { if(k==j||k==i||(s&(1<<k))==0||gp[j][k]==0)continue; int ss=s-(1<<i); if(dp[ss][j][k] ==-1)continue; long long tem=isv[i]+isv[i]*isv[j]+dp[ss][j][k]; if(gp[i][k]) tem+=isv[i]*isv[j]*isv[k]; if(tem>dp[s][i][j]) { dp[s][i][j]=tem; isl[s][i][j]=isl[ss][j][k]; } else if(tem==dp[s][i][j]) isl[s][i][j]+=isl[ss][j][k]; } } }*/ long long ans=-1,count=0; int ss=(1<<n)-1; for(int i=0;i<n;i++) for(int j=0;j<n;j++) { if(i==j) continue; if(ans<dp[ss][i][j]) { ans=dp[ss][i][j]; count=isl[ss][i][j]; } else if(dp[ss][i][j]==ans) count+=isl[ss][i][j]; } if(ans==-1) printf("0 0\n"); else printf("%lld %lld\n",ans,count/2); } int main() { int c,x,y; scanf("%d",&c); while(c--) { memset(gp,0,sizeof(gp)); scanf("%d%d",&n,&m); for(int i=0;i<n;i++) scanf("%lld",&isv[i]); if(n==1) { printf("%lld 1\n",isv[0]); continue; } for(int i=0;i<m;i++) { scanf("%d%d",&x,&y); gp[x-1][y-1]=gp[y-1][x-1]=1; } DP(); } return 0; } Followed by:
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