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acm十大未解之谜有一种想死的感觉,两段代码检查了10+遍,毫无差别,但是换成下面注释里面的就A,不换就WA。谁能够解释这一神奇的现象?
#include<cstdio>
#include<cstring>
#include<string>
#include<iostream>
#include<algorithm>
#include<cmath>
using namespace std;
int n,m;
int gp[14][14];
long long dp[1<<14][14][14],isv[14],isl[1<<14][14][14];
void DP()
{
long long tem;
memset(dp,-1,sizeof(dp));
memset(isl,0,sizeof(isl));
for(int i=0;i<n;i++)
for(int j=0;j<n;j++)
{
if(i==j||gp[i][j]==0)continue;
tem=(1<<j)+(1<<i);
dp[tem][i][j]=isv[i]+isv[j]+isv[i]*isv[j];
isl[tem][i][j]=1;
}
for(int s=0;s<(1<<n);s++)
for(int i=0;i<n;i++)
{
if((s&(1<<i))==0)continue;
for(int j=0;j<n;j++)
{
if(i==j||(s&(1<<j))==0||gp[i][j]==0)continue;
for(int k=0;k<n;k++)
{
if(k==j||k==i||(s&(1<<k))==0||gp[j][k]==0)continue;
int ss=s-(1<<i);
if(dp[ss][j][k]==-1)continue;
long long tem=isv[i]+isv[i]*isv[j]+dp[ss][j][k];
if(gp[i][k]) tem+=isv[i]*isv[j]*isv[k];
if(tem>dp[s][j][j])
{
dp[s][i][j]=tem;
isl[s][i][j]=isl[ss][j][k];
}
else
if(tem==dp[s][j][j])
isl[s][i][j]+=isl[ss][j][k];
}
}
}
/*
for(int s=0;s<(1<<n);s++)
for(int i=0;i<n;i++)
{
if((s&(1<<i))==0)continue;
for(int j=0;j<n;j++)
{
if(i==j||(s&(1<<j))==0||gp[i][j]==0)continue;
for(int k=0;k<n;k++)
{
if(k==j||k==i||(s&(1<<k))==0||gp[j][k]==0)continue;
int ss=s-(1<<i);
if(dp[ss][j][k] ==-1)continue;
long long tem=isv[i]+isv[i]*isv[j]+dp[ss][j][k];
if(gp[i][k]) tem+=isv[i]*isv[j]*isv[k];
if(tem>dp[s][i][j])
{
dp[s][i][j]=tem;
isl[s][i][j]=isl[ss][j][k];
}
else
if(tem==dp[s][i][j])
isl[s][i][j]+=isl[ss][j][k];
}
}
}*/
long long ans=-1,count=0;
int ss=(1<<n)-1;
for(int i=0;i<n;i++)
for(int j=0;j<n;j++)
{
if(i==j)
continue;
if(ans<dp[ss][i][j])
{
ans=dp[ss][i][j];
count=isl[ss][i][j];
}
else if(dp[ss][i][j]==ans)
count+=isl[ss][i][j];
}
if(ans==-1)
printf("0 0\n");
else
printf("%lld %lld\n",ans,count/2);
}
int main()
{
int c,x,y;
scanf("%d",&c);
while(c--)
{
memset(gp,0,sizeof(gp));
scanf("%d%d",&n,&m);
for(int i=0;i<n;i++)
scanf("%lld",&isv[i]);
if(n==1)
{
printf("%lld 1\n",isv[0]);
continue;
}
for(int i=0;i<m;i++)
{
scanf("%d%d",&x,&y);
gp[x-1][y-1]=gp[y-1][x-1]=1;
}
DP();
}
return 0;
}
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