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WA的同学进,这题太恶心了!!

Posted by speedcell4 at 2011-08-17 16:25:21 on Problem 2446
In the next k lines, there is a pair of integers (x, y) in each line, which represents a hole in the y-th row, the x-th column.
注意这句话……汗……
附16MS代码:
#include<iostream>
#define SIZE 33
using namespace std;
int t[SIZE][SIZE][2];
bool a[SIZE][SIZE][SIZE][SIZE],v[SIZE][SIZE];
int n,m,k,x,y;
int go[4][2]={{1,0},{-1,0},{0,1},{0,-1}};
bool canGo(int x,int y)
{
    return (x>=0&&y>=0)&&(x<n&&y<m);
}
bool find(int x,int y)
{
    for(int i=0;4-i>0;i++)
    {
        int xx=x+go[i][0];
        int yy=y+go[i][1];
        if(canGo(xx,yy)) 
        if(v[xx][yy]==false&&a[x][y][xx][yy]==true)
        {
            v[xx][yy]=true;
            if((t[xx][yy][0]==-1&&t[xx][yy][1]==-1)||find(t[xx][yy][0],t[xx][yy][1]))
            {
                t[xx][yy][0]=x;
                t[xx][yy][1]=y;
                return true;
            }
        }
    }
    return false;
}
int findMatch(void)
{
    int count=0;
    for(int i=0;n-i>0;i++)
    {
        for(int j=0;m-j>0;j++)
        {
            if((i+j)%2==0) continue;
            else
            {
                memset(v,false,sizeof(v));
                if(find(i,j)) count++;
            }
        }
    }
    return count;
}
int main()
{
    while(scanf("%d %d %d",&n,&m,&k)!=EOF)
    {
        memset(t,-1,sizeof(t));
        memset(a,true,sizeof(a));
        for(int i=0;k-i>0;i++)
        {
            scanf("%d %d",&y,&x);
            x--;
            y--;
            if((x+y)%2==0)
            {
                for(int i=0;4-i>0;i++)
                {
                    int xx=x+go[i][0];
                    int yy=y+go[i][1];
                    if(canGo(xx,yy)) a[xx][yy][x][y]=false;
                }
            }
            else
            {
                for(int i=0;4-i>0;i++)
                {
                    int xx=x+go[i][0];
                    int yy=y+go[i][1];
                    if(canGo(xx,yy)) a[x][y][xx][yy]=false;
                }
            }
        }
        if(k%2==1)
        {
            printf("NO\n");
            continue;
        }
        if((2*findMatch()+k)==(m*n)) printf("YES\n");
        else printf("NO\n");
    }
    return 0;
}

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