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拜托哪个善良的牛人帮我看一下,为什么那个s数组求得不对啊!?明明这个道理很对啊!aUb=a+b-a^b啊#include<cstdio> #include<cstdlib> #include<cmath> #include<string> int d[16][9][9][9][9],s[9][9][9][9],mtr[9][9],ss[9][9]; int MIN(int a ,int b) { if(a<b)return a; else return b; } int main() { int i,n,k,j,a,temp=0,sum=0,x1,x2,y1,y2; double ave,tot=0; scanf("%d",&n); for(i=0;i<8;++i) { for(j=0;j<8;++j) { scanf("%d",&mtr[i][j]); sum+=mtr[i][j]; tot+=mtr[i][j]; if(!i)ss[i][j]=sum; else ss[i][j]=ss[i-1][j]+sum; if(j==7)sum=0; } } ave=tot/n; for(x1=0;x1<8;++x1) for(y1=0;y1<8;++y1) for(x2=x1;x2<8;++x2) for(y2=y1;y2<8;++y2) { if(x1==0||y1==0)temp=ss[x2][y2]; else temp=ss[x2][y2]+ss[x1-1][y1-1]-ss[x1-1][y2]-ss[x2][y1-1]; s[x1][y1][x2][y2]=temp*temp; d[0][x1][y1][x2][y2]=s[x1][y1][x2][y2]; } /* for (x1=0; x1<8; x1++) { for (y1=0; y1<8; y1++) { for (x2=x1; x2<8; x2++) { sum = 0; for (y2=y1; y2<8; y2++) { sum += mtr[x2][y2]; if (x2 == x1) { s[x1][y1][x2][y2] = sum; } else { s[x1][y1][x2][y2] = s[x1][y1][x2-1][y2] + sum; } s[x1][y1][x2][y2] *= s[x1][y1][x2][y2]; d[0][x1][y1][x2][y2] = s[x1][y1][x2][y2] ; } } } } */ for(k=1;k<=n;++k) for(x1=0;x1<8;++x1) for(y1=0;y1<8;++y1) for(x2=x1;x2<8;++x2) for(y2=y1;y2<8;++y2) { d[k][x1][y1][x2][y2]=2000000000; for(i=x1;i<x2;++i)//横切 { d[k][x1][y1][x2][y2]=MIN(d[k][x1][y1][x2][y2],d[k-1][x1][y1][i][y2]+s[i+1][y1][x2][y2]); d[k][x1][y1][x2][y2]=MIN(d[k][x1][y1][x2][y2],d[k-1][i+1][y1][x2][y2]+s[x1][y1][i][y2]); } for(i=y1;i<y2;++i)//竖切 { d[k][x1][y1][x2][y2]=MIN(d[k][x1][y1][x2][y2],d[k-1][x1][y1][x2][i]+s[x1][i+1][x2][y2]); d[k][x1][y1][x2][y2]=MIN(d[k][x1][y1][x2][y2],d[k-1][x1][i+1][x2][y2]+s[x1][y1][x2][i]); } } /*for (k=1; k<=n-1; k++) { for (x1=0; x1<8; x1++) { for (y1=0; y1<8; y1++) { for (x2=x1; x2<8; x2++) { for (y2=y1; y2<8; y2++) { d[k][x1][y1][x2][y2] = 2000000000; for (a=x1; a<x2; a++) { temp = MIN(d[k-1][x1][y1][a][y2] + s[a+1][y1][x2][y2], d[k-1][a+1][y1][x2][y2] + s[x1][y1][a][y2]); d[k][x1][y1][x2][y2] = MIN(d[k][x1][y1][x2][y2], temp); } for (a=y1; a<y2; a++) { temp = MIN(d[k-1][x1][y1][x2][a] + s[x1][a+1][x2][y2], d[k-1][x1][a+1][x2][y2] + s[x1][y1][x2][a] ); d[k][x1][y1][x2][y2] = MIN(d[k][x1][y1][x2][y2], temp); } } } } } } */ double ret = sqrt((double)d[n-1][0][0][7][7]/(double)n-ave*ave); printf("%.3f\n",ret); return 0; } Followed by:
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