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Re:C++ 就AC G++ 是WA 好诡异的测试~~~(附代码)In Reply To:C++ 就AC G++ 是WA 好诡异的测试~~~(附代码) Posted by:447409410 at 2011-07-10 10:56:49 > #include<iostream> > #include<cstdio> > #include<string> > #include<cstring> > #include<cmath> > #include<algorithm> > > #define exp 2.718281828 > > using namespace std; > > double tem,dew,hum; > double h,e; > char start,indor,end; > double a,b; > > int main() > { > int cacolate(char &a, double &x, char &b, double &y); > > while(scanf("%c",&start)!=EOF && (start!='E')) > { > scanf("%lf %c %lf",&a,&indor,&b); > getchar(); > cacolate(start,a,indor,b); > } > > return 0; > } > > int cacolate(char &a, double &x, char &b, double &y) > { > if(a=='T' && b=='D') > { > tem=x; > dew=y; > e=6.11*pow(exp,(5417.7530 * ((1/273.16) - (1/(dew+273.16))))); > h=(0.5555)* (e - 10.0); > hum=tem+h; > // return hum; > cout<<"T "; > printf("%.1lf",tem); > cout<<" D "; > printf("%.1lf",dew); > cout<<" H "; > printf("%.1lf\n",hum); > return 0; > } > else if(a=='D' && b=='T') > { > tem=y; > dew=x; > e=6.11*pow(exp,(5417.7530 * ((1/273.16) - (1/(dew+273.16))))); > h=(0.5555)* (e - 10.0); > hum=tem+h; > // return hum; > cout<<"T "; > printf("%.1lf",tem); > cout<<" D "; > printf("%.1lf",dew); > cout<<" H "; > printf("%.1lf\n",hum); > return 0; > } > else if(a=='D' && b=='H') > { > dew=x; > hum=y; > e=6.11*pow(exp,(5417.7530 * ((1/273.16) - (1/(dew+273.16))))); > h=(0.5555)* (e - 10.0); > tem=hum-h; > cout<<"T "; > printf("%.1lf",tem); > cout<<" D "; > printf("%.1lf",dew); > cout<<" H "; > printf("%.1lf\n",hum); > return 0; > } > else if(a=='H' && b=='D') > { > dew=y; > hum=x; > e=6.11*pow(exp,(5417.7530 * ((1/273.16) - (1/(dew+273.16))))); > h=(0.5555)* (e - 10.0); > tem=hum-h; > cout<<"T "; > printf("%.1lf",tem); > cout<<" D "; > printf("%.1lf",dew); > cout<<" H "; > printf("%.1lf\n",hum); > return 0; > } > else if(a=='H' && b=='T') > { > hum=x; > tem=y; > h=hum-tem; > e=h/0.5555+10.0; > dew=1/(1/273.16-log(e/6.11)/5417.7530)-273.16; > cout<<"T "; > printf("%.1lf",tem); > cout<<" D "; > printf("%.1lf",dew); > cout<<" H "; > printf("%.1lf\n",hum); > return 0; > } > else if(a=='T' && b=='H') > { > hum=y; > tem=x; > h=hum-tem; > e=h/0.5555+10.0; > dew=1/(1/273.16-log(e/6.11)/5417.7530)-273.16; > cout<<"T "; > printf("%.1lf",tem); > cout<<" D "; > printf("%.1lf",dew); > cout<<" H "; > printf("%.1lf\n",hum); > return 0; > } > } Followed by: Post your reply here: |
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