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如此的水题#include <iostream> #include <cmath> using namespace std; int main() { int n,m; cin>>n; for(int i=1;i<=n;i++) { cin>>m; int i=0; int sum=0; for(int p=2;m%p==0;p=p*2) i++; for(int j=0;j<=i-1;j++) { sum +=pow(2,j); } cout<<m-sum<<" "<<m+sum<<endl; } return 0; } Followed by: Post your reply here: |
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