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水题花了好久……f[i]= min (f[i-1]+1, f[k]+w(k+1,i)) w表示k+1~i匹配成功需要删除的最少个数 本来枚举了k，结果超时。。改成从i开始直接往前匹配63ms 汗。。 Followed by: Post your reply here: |
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