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这陀题硬是一下子高不清楚做什么,贡献了2次WA#include<stdio.h> main() { int n,i,j,a[100][100],sum[100]={0},count=0; scanf("%d",&n); for(i=0;i<n;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); } } for(i=0;i<n;i++) { for(j=0;j<n;j++) { if(a[i][j]>a[j][i]) sum[i]++; } if(i&&(sum[i]-sum[0]>0)) { sum[0]=sum[i]; count=i; } } printf("%d",count+1); } Followed by: Post your reply here: |
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