Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
判断长度差一的字符串能否转化为另一个。int Near(char *s,char *t,int l) {//lens - lent == 1 ; s[] to t[] int c,i; for(i=c=0;i<l&&c<2;){ if(s[i+c]!=t[i]) c++; else i++; } return 2-c; } Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator