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O(N^2)直接水啊,代码不到600B。核心代码: void work() { for (int i = n; i >= 1; i--){ ans[i] = num[i] + f[num[i]]; for (int j = num[i]; j < i; j++) f[j] = f[j + 1] + 1; } } 不过稍微有点慢,100+ms水过。 Followed by: Post your reply here: |
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