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纠正了,是递归里存在小问题,附上0ms AC代码~In Reply To:最大独立集问题,等价为补图最大团问题,用DP+DFS求解,但WA,求助~~ Posted by:tbziy2 at 2011-05-28 00:00:39 #include<stdio.h> #include<memory.h> #include<vector> #include<iostream> #include<sstream> #include<algorithm> #include<memory.h> using namespace std; int N,V; int **g, *dp, **stk, mx; vector<int> vetexlist; vector<int> maxcliquelist; int dfs(int n, int ns, int dep){ int i, j, k, p, cnt; if (0 == ns) { if (dep >= mx) { mx = dep; vector<int>::iterator iter = vetexlist.begin(); maxcliquelist.clear(); for(;iter!=vetexlist.end();iter++) { maxcliquelist.push_back(*iter); } } return 1; } for (i = 0; i < ns; i++) { k = stk[dep][i]; cnt = 0; if (dep + n - k <= mx) return 0; if (dep + dp[k] <= mx) return 0; for (j = i + 1; j < ns; j++) { p = stk[dep][j]; if (g[k][p]) { stk[dep + 1][cnt++] = p; } } vetexlist.push_back(k); dfs(n, cnt, dep + 1); vetexlist.pop_back(); } return 1; } int clique(int n) { int i, j, ns; for (mx = 0, i = n - 1; i >= 0; i--) { for (ns = 0, j = i + 1; j < n; j++) { if (g[i][j]) { stk[1][ ns++ ] = j; } } vetexlist.push_back(i); dfs(n, ns, 1); vetexlist.pop_back(); dp[i] = mx; } return mx; } int main() { //ostringstream ofs; scanf("%d",&N); int i,j,k,v1,v2; int edgeCount; for(i=0;i<N;i++) { scanf("%d%d",&V,&edgeCount); g = new int*[V]; dp = new int[V]; memset(dp,0,sizeof(int)*V); stk = new int*[V]; for(j=0;j<V;j++) { g[j] = new int[V]; stk[j] = new int[V]; for(k=0;k<V;k++) { g[j][k] = 1; } } for(j=0;j<edgeCount;j++) { scanf("%d%d",&v1,&v2); g[v1-1][v2-1] = 0; g[v2-1][v1-1] = 0; } cout<<clique(V)<<endl; sort(maxcliquelist.begin(),maxcliquelist.end()); vector<int>::iterator iter = maxcliquelist.begin(); //ofs<<*iter+1; for(;iter!=maxcliquelist.end();iter++) { cout<<*iter+1<<" "; } cout<<endl; } //cout<<ofs.str(); return 0; } Followed by: Post your reply here: |
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