| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
代码接近,贴出来抓个爪 o(∩_∩)oIn Reply To:代码较简洁,交流下 Posted by:on_pku at 2009-12-21 18:20:42 > //6266010 on_pku 3126 Accepted 732K 16MS G++ 2214B 2009-12-21 18:18:46
> #include<iostream>
> #include<cstdlib>
> #include<cstdio>
> #include<queue>
> using namespace std;
> const int SIZE = 10000;
> bool prime[SIZE];
> int step[SIZE];
> int base[4] = {1,10,100,1000};
> int main()
> {
> for(int i = 0; i < SIZE; i++)prime[i] = true;
>
> for(int i = 2; i < SIZE; i++){
> if(prime[i]){
> for(int j = 2; i*j < SIZE; j++)
> prime[i*j] = false;
> }
> }
>
> int t,a,b,d[4];
> scanf("%d",&t);
> while(t--){
> scanf("%d %d",&a,&b);
> fill(step,step+SIZE,0);
> queue<int>path;
> path.push(a);
> step[a] = 1;
> while(!path.empty()){
> int ori = path.front();
> if(ori == b)break;
> path.pop();
> d[0] = ori%10; d[1] = ori%100/10;
> d[2] = ori%1000/100; d[3] = ori/1000;
> int newnum;
> for(int i = 0; i < 10; i ++){
> newnum = ori - d[3]*1000 + i*1000;
> if(i != 0 && prime[newnum] && !step[newnum]){
> step[newnum] = step[ori] + 1;
> path.push(newnum);
> }
> for(int k = 0; k < 3; k++){
> newnum = ori - d[k]*base[k] + i*base[k];
> if(prime[newnum] && !step[newnum]){
> step[newnum] = step[ori] + 1;
> path.push(newnum);
> }
> }
> }
> }
> printf("%d\n",step[b]-1);
> }
> return 0;
> }
// 8608709 lsz 3126 Accepted 288K 0MS C++ 1286B 2011-05-07 20:34:28
#include <iostream>
#include <queue>
#include <utility>
#include <complex>
using namespace std;
int main()
{
const int N = 10000;
const int root = (int)sqrt((double)N);
bool not_prime[N] = {false};
not_prime[0] = not_prime[1] = true;
for (int i=2; i<=root; i++)
{
if (!not_prime[i])
{
for (int j=i+i; j<N; j+=i)
{
not_prime[j] = true;
}
}
}
const int divider[4] = {1000, 100, 10, 1};
int n;
cin>>n;
while (n--)
{
int a, b;
cin>>a>>b;
if (a == b)
{
cout<<0<<endl;
continue;
}
bool visited[N] = {false};
queue<pair<int,int>> q;
pair<int,int> p = pair<int,int>(a, 0);
q.push(p);
visited[a] = true;
while (!q.empty() && (p = q.front()).first != b)
{
q.pop();
for (int i=0; i<4; i++)
{
int digit = (p.first / divider[i]) % 10;
for (int j=0; j<=9; j++)
{
if ((j != digit) && (i > 0 || j > 0))
{
int number = p.first + (j - digit) * divider[i];
if (!visited[number] && !not_prime[number])
{
q.push(pair<int,int>(number, p.second + 1));
visited[number] = true;
}
}
}
}
}
if (p.first == b)
{
cout<<p.second<<endl;
}
else
{
cout<<-1<<endl;
}
}
return 0;
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator