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把已有的边权强行赋成0然后直接prim就行了In Reply To:怎么过不了,老是wrong 想看看牛人怎么写的 Posted by:lagrange at 2005-05-03 01:08:55 > #include <stdio.h> > #define MAXN 101 > int n,q,xx[MAXN][MAXN]; > > void conn(int a,int b) > { > int i,j,i0,j0,temp; > if (a<b) > {temp=a;a=b;b=temp;} > for(i=1;i<=n;i++) > { > xx[b][i]=((xx[a][i]<xx[b][i])?xx[a][i]:xx[b][i]); > xx[i][b]=((xx[i][a]<xx[i][b])?xx[i][a]:xx[i][b]); > } > for(i=a;i<=n-1;i++) > for(j=1;j<=n;j++) > xx[i][j]=xx[i+1][j]; > for(i=1;i<=n-1;i++) > for(j=a;j<=n-1;j++) > xx[i][j]=xx[i][j+1]; > n--; > } > > void input() > { > int i,j,a,b; > scanf("%d",&n); > for(i=1;i<=n;i++) > { > for(j=1;j<=n;j++) > scanf("%d",&xx[i][j]); > } > scanf("%d",&q); > for(i=1;i<=q;i++) > { > scanf("%d%d",&a,&b); > conn(a,b); > } > } > > int solve() > { > int i,j,ci,cj,y,min; > y=0; > while(n!=1) > { > min=10000; > for(i=1;i<=n;i++) > for(j=1;j<=n;j++) > if(xx[i][j]<min&&i!=j) > { > min=xx[i][j]; > ci=i;cj=j; > } > y+=xx[ci][cj]; > conn(ci,cj); > } > return y; > } > > main() > { > input(); > printf("%d\n",solve()); > } Followed by:
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