> #include <stdio.h>
> void main()
> {
> 	float xinxi[100000],sum=0;
> 	long i;
> 	for (i=1;i<100000;i++)
> 	{
> 		sum+=1.000000/(2*i);
> 		xinxi[i]=sum;
> 	}
> 	printf("Cards  Overhang\n");
> 	while (scanf("%ld",&i)!=-1)
> 		printf("%5d%10.3f\n",i,xinxi[i]);
> }

• 谢谢好心人,当年是多么稚嫩啊... (0) ferret_chao 2005-09-20 23:30:36
• Re:float改成double就好了 (24) houxuanfelix 2006-07-14 22:41:22
  • 对牌的个数n作归纳，用到杠杆平衡条件 (28) bufan_2001 2006-08-16 19:05:53
    • Re:对牌的个数n作归纳，用到杠杆平衡条件 (23) ccred 2007-08-05 12:37:45
• Re:float改成double就好了 (9) done 2007-03-09 15:22:15