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经验帖这个题目要考虑二分的对象,二分弧度的话范围就是[0,PI],而二分半径R的范围是[L/2,INF],还有其他对象可选. 当然导致的精度会不一样的,而且效率也不同的, 所以作者出这个题目是有意图的,传达一个二分对象的选择的问题. 不需要什么迭代的,二分弧度0ms过. Followed by: Post your reply here: |
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