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水题,不解释#include <stdio.h> int main(){ int i,j,k,n,a,b; char s[5],t[5]; s[4]=t[4]='\0'; scanf("%d",&n); for(i=0;i<n;i++){ a=b=0; scanf("%s %s",s,t); for(j=0;j<4;j++) if(s[j]==t[j]) a++; for(j=0;j<4;j++){ for(k=0;k<4;k++) if(s[j]==t[k]&&j!=k) b++; } printf("%dA%dB\n",a,b); } return 0; } Followed by: Post your reply here: |
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