| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
Re:用哈夫曼树做的竟然错了,哪位大牛找出错哪了(用了_int64)In Reply To:用哈夫曼树做的竟然错了,哪位大牛找出错哪了(用了_int64) Posted by:tanjing at 2010-08-23 11:09:32 > #include <iostream>
> #include <cstdlib>
> using namespace std;
>
> const int MaxValue = 10000; //初始设定的权值最大值
>
> struct HaffNode //哈夫曼树的结点结构
> {
> int weight; //权值
> int flag; //标记
> int parent; //双亲结点下标
> int leftChild; //左孩子下标
> int rightChild; //右孩子下标
> };
>
>
> void Haffman(int weight[], int n, HaffNode haffTree[])
> //建立叶结点个数为n权值为weight的哈夫曼树haffTree
> {
> int j, m1, m2, x1, x2;
> //哈夫曼树haffTree初始化。n个叶结点的哈夫曼树共有2n-1个结点
> for(int i = 0; i < 2 * n - 1 ; i++) {
> if(i < n) haffTree[i].weight = weight[i];
> else haffTree[i].weight = 0;
> haffTree[i].parent = 0;
> haffTree[i].flag = 0;
> haffTree[i].leftChild = -1;
> haffTree[i].rightChild = -1;
> }
> //构造哈夫曼树haffTree的n-1个非叶结点
> for(int i = 0;i < n-1;i++) {
> m1 = m2 = MaxValue;
> x1 = x2 = 0;
> for(j = 0; j < n+i;j++) {
> if (haffTree[j].weight < m1 && haffTree[j].flag == 0){
> m2 = m1;
> x2 = x1;
> m1 = haffTree[j].weight;
> x1 = j;
> }
> else if(haffTree[j].weight < m2 && haffTree[j].flag == 0){
> m2 = haffTree[j].weight;
> x2 = j;
> }
> }
> //将找出的两棵权值最小的子树合并为一棵子树
> haffTree[x1].parent = n+i;
> haffTree[x2].parent = n+i;
> haffTree[x1].flag = 1;
> haffTree[x2].flag = 1;
> haffTree[n+i].weight = haffTree[x1].weight+haffTree[x2].weight;
> haffTree[n+i].leftChild = x1;
> haffTree[n+i].rightChild = x2;
> }
> }
>
> int main(){
> int n;
> cin>>n;
> if(n==1)
> {
> cout<<0<<endl;
> return 0;
> }
> long long sum=0;
> int weight[20005];
> for(int i=0;i<n;i++)
> cin>>weight[i];
> HaffNode *myHaffTree = new HaffNode[2*n-1];
> Haffman(weight, n, myHaffTree);
> for(int i = n; i < 2*n-1; i++) { //非叶子结点的和
> sum+=myHaffTree[i].weight;
> }
> printf("%I64d\n",sum);
> //system("pause");
> }
Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator