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Re:错了无数次了,实在没招了。。帮我看一下吧。。狂谢不止In Reply To:错了无数次了,实在没招了。。帮我看一下吧。。狂谢不止 Posted by:jjh at 2005-11-12 21:57:05 #include<iostream> using namespace std; int isdigit(char c) { if(c>='0'&&c<='9') return 1; return 0; } int isletter(char c) { if(c>='A'&&c<='Z'||c>='a'&&c<='z') return 1; return 0; } int isupper(char c) { if(c>='A'&&c<='Z') return 1; return 0; } int ismark(char c) { if(!isletter(c)&&!isdigit(c)&&c!=' ') return 1; return 0; } int un(char c) { if(c!='A'&&c!='a'&&c!='I') return 1; return 0; } int main() { char s[85]; int i,l,flag; while(1) { gets(s); if(s[0]=='#') break; for(l=0;s[l]!='\0';l++); flag=1; if (l == 1&&un(s[0])) flag = 0; for(i=0;i<l-1&&flag==1;i++) { if(isupper(s[i])&&isupper(s[i+1])) flag=0; else if(isletter(s[i])&&isdigit(s[i+1])|| isletter(s[i+1])&&isdigit(s[i])) flag=0; else if(i>=1&&i<=(l-3)&&s[i]==' '&&s[i+2]==' '&&un(s[i+1])) flag=0; else if(i==(l-2)&&s[i]==' '&&un(s[i+1])) flag=0; else if(i==0&&s[i+1]==' '&&un(s[i])) flag=0; else if(ismark(s[i])&&ismark(s[i+1])&&s[i]!='"'&&s[i+1]!='"') flag=0; } if(flag==0) printf("suspicious\n"); else printf("OK\n"); } return 0; } Followed by: Post your reply here: |
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