| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
注意r是double类型AC代码
#include <iostream>
#include <cstring>
#include <string>
#include <stdio.h>
#include <stdlib.h>
#include <cmath>
using namespace std;
double pi=3.141592653589793;
int main()
{
int n,i;
double sum,r;
double data[501][2];
while(scanf("%d %lf",&n,&r)!=EOF)
{
sum=0;
for(i=0;i<n;i++)
{
scanf("%lf %lf",&data[i][0],&data[i][1]);
if(i>0)
sum +=sqrt(pow(data[i][0]-data[i-1][0],2)+pow(data[i][1]-data[i-1][1],2));
}
sum+=sqrt(pow(data[n-1][0]-data[0][0],2)+pow(data[n-1][1]-data[0][1],2));
sum+=2*pi*r;
printf("%.2lf\n",sum);
}
return 0;
}
Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator