#include<iostream.h>
void main()
{
	long double a,b;
	long double d[480]={1,2};
	int i,m;
	for(i=2;i<479;i++)
		d[i]=d[i-1]+d[i-2];
	cin>>a>>b;
	while(a!=0||b!=0)
	{
		m=0;
		for(i=0;i<479;i++)
			if(d[i]>=a&&d[i]<=b)
				m++;
		cout<<m<<endl;
		cin>>a>>b;
	}
}

• Re:这么简单怎么是output limit exceeded 啊 (345) frkstyc 2005-04-29 16:25:37
  • Re:这么简单怎么是output limit exceeded 啊 (54) 00448713 2005-04-29 16:32:38
    • 写高精度 (0) frkstyc 2005-04-29 19:23:24