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郁闷,,,这是精度问题吗????WA了一片,,最后把判断相交的 < 改为<=就过了,,,,我觉得2者是等价的啊,,如果相等的话,,也可以看作不相交啊,,因为求的最短路,,总可以将距离通过中间擦边那个点传递过去的,,Followed by:
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