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Re:晚上怎么改都WA,早上起来,一次AC,还是早上清醒啊!!!In Reply To:晚上怎么改都WA,早上起来,一次AC,还是早上清醒啊!!! Posted by:sdau_085111 at 2011-01-08 07:28:10 2 2 10 ABBAS SALAM AAAAA AAAAA 这组数据你的代码输出有错的哦~ > /* Author : yan > * Question : POJ 2895 Best SMS to Type > * Data && Time : Friday, January 07 2011 11:16 PM > * Compiler : gcc (Ubuntu 4.4.3-4ubuntu5) 4.4.3 > */ > #include<stdio.h> > //对应键需要按的次数,最后一个是空格 > int dic[]={1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,4,1,2,3,1,2,3,4,1}; > //对应字符对应键 > int dic1[]={2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,9,9,9,9,1}; > > char mesg[1005]; > > int main() > { > //freopen("input","r",stdin); > int test; > int press,wait; > int i; > int ans; > int cnt;//空格个数 > scanf("%d",&test); > while(test--) > { > ans=0;cnt=0; > scanf("%d %d",&press,&wait); > getchar(); > gets(mesg); > for(i=0;mesg[i+1]!='\0';i++) > { > if(mesg[i+1]==32) mesg[i+1]='A'+26; > if( dic1[mesg[i]-'A']==dic1[mesg[i+1]-'A'] && dic1[mesg[i]-'A']!=1 ) > { > ans+=press*dic[mesg[i]-'A']+wait; > //printf("%d\n",press*dic[mesg[i]-'A']+wait); > } > else > { > ans+=press*dic[mesg[i]-'A']; > //printf("%d\n",press*dic[mesg[i]-'A']); > } > } > //printf("%c",mesg[i]); > ans+=press*dic[mesg[i]-'A']; > printf("%d\n",ans); > } > return 0; > } Followed by: Post your reply here: |
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