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Re:无聊的数学题，推导如下

Posted by jackl at 2011-02-16 13:58:48 on Problem 1045
In Reply To:Re:无聊的数学题，推导如下 Posted by:jackl at 2011-02-16 13:57:28

> //公式推导：V2=iR=CR d/dt(Vs*cos(wt)-Vr*cos(wt+b))=Vrcos(wt+b)
> //          CRw(sin(wt+b)-sin(wt))=Vr*cos(wt+b)
> //          令t=0化简得：   tan(b)=1/(CRw)-------------(1)
> //          令wt+b=0化简得：Vr=CRwVs*sin(b)------------(2)
> //          由(1),(2)得：   Vr=CRwVs/sqrt(1+(CRw)^2))
//过程好像错了一点第二步是CRw(Vrsin(wt+b)-Vssin(wt))=Vr*cos(wt+b)

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