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连变态输入都考虑了还是不能通过……能给出错误的数据点吗?

Posted by phantomr at 2005-04-28 09:58:37 on Problem 1013
In Reply To:我觉得这道题的思路比较清晰啊 为什么总是WA呢?实在是想不出什么疏漏了……请高手指点 Posted by:phantomr at 2005-04-27 17:19:25
#include<stdio.h>
#include<string.h>
main()
{
    char left[20],right[20],result[5],input[3][12],fact[12];
    int i,j,t;
    scanf("%d",&t);  //the number of cases
    
    for(;t>0;t--)
    {
    for(i=0;i<3;i++)
    for(j=0;j<12;j++)
    input[i][j]='?';
    
    for(j=0;j<3;j++)
    {
    scanf("%s %s %s",left,right,result);//input condition
    
    if(strcmp(result,"even")==0)
    {for(i=0;i<12;i++)
     input[j][i]='?';    //can be all the possibilities 
     for(i=0;left[i]!='\0';i++)
     {input[j][left[i]-65]=(input[j][left[i]-65]==0)? '?':0;   //real
      input[j][right[i]-65]=(input[j][right[i]-65]==0)? '?':0;}
    } 
    else
   {for(i=0;i<12;i++)
    input[j][i]=0;
    if(strcmp(result,"up")==0)
    for(i=0;left[i]!='\0';i++)
    {input[j][left[i]-65]=(input[j][left[i]-65]==-1)? 0:1;  //possibly heavy
     input[j][right[i]-65]=(input[j][right[i]-65]==1)? 0:-1;}  //possibly light
    else
    for(i=0;left[i]!='\0';i++)
    {input[j][left[i]-65]=(input[j][left[i]-65]==1)? 0:-1;   //'A'-65=0
     input[j][right[i]-65]=(input[j][right[i]-65]==-1)? 0:1;}
    } 
    }
    
    for(i=0;i<12;i++)
    {if(input[0][i]==0||input[1][i]==0||input[2][i]==0)
     continue;
     else
     if(input[0][i]==1||input[1][i]==1||input[2][i]==1)
     {strcpy(fact,"heavy");
      break;}
     else
     {strcpy(fact,"light");
      break;}
    }
    printf("%c is the counterfeit coin and it is %s.\n",i+65,fact);   
    }     
}

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