Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
没问题,正常的都3000+In Reply To:用RMQ怎么要3000+???各位大牛看下我的代码 Posted by:mmx21 at 2010-06-06 15:28:09 > #include "stdio.h" > #include "string.h" > #include "math.h" > > #define L 50005 > int N,Q; > int A[L]; > int M[L][20]; > int S[L][20]; > #define max( x, y ) ( (x) > (y) ? (x) : (y) ) > #define min( x, y ) ( (x) < (y) ? (x) : (y) ) > > void RMQ() > { > int i,j; > for(i=1;i<=N;i++) > { > M[i][0]=A[i]; > S[i][0]=A[i]; > } > for(j=1;(1<<j)<=N;j++) > { > for(i=1;i+(1<<j)-1<=N;i++) > { > M[i][j]=max(M[i][j-1],M[i+(1<<(j-1))][j-1]); > S[i][j]=min(S[i][j-1],S[i+(1<<(j-1))][j-1]); > } > } > } > > int main() > { > int i,k; > int a,b; > memset(M,0,sizeof(M)); > memset(S,0,sizeof(S)); > scanf("%d %d",&N,&Q); > for(i=1;i<=N;i++) > scanf("%d",&A[i]); > RMQ(); > while(Q--) > { > scanf("%d %d",&a,&b); > k=(int)(log((double)(b-a+1))/log(2.0)); > printf("%d\n",max(M[a][k],M[b-(1<<k)+1][k])-min(S[a][k],S[b-(1<<k)+1][k])); > } > return 0; > } > Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator