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WA到死啊,,我是放弃了,,,哪位大牛进来看看????代码有注释,,,#include <iostream>
using namespace std;
#define max(a,b) (a>b?a:b)
const int N=810;
const int oo=-(1<<30);
int dp[210][21][N],d[210],p[210],q[210],end;
//q[]是存最后的选择了谁的,end是q[]的大小
void dfs(int i,int j,int k)//递归寻找选择了谁,存到q[]里,,
{
if(i==0||j==0)
return;
if(dp[i-1][j][k]<dp[i-1][j-1][k-d[i]+p[i]]+d[i]+p[i])
{
q[end++]=i;
dfs(i-1,j-1,k-d[i]+p[i]);
}
else
dfs(i-1,j,k);
}
int main()
{
int n,m,num=1;//num是用来输出#后边那个数字,,
while(scanf("%d%d",&n,&m)&&n)
{
int i,j,k;
for(i=1;i<=n;i++)
scanf("%d%d",&p[i],&d[i]);
for(i=0;i<=n;i++)//负初值
for(j=0;j<=m;j++)
for(k=0;k<=800;k++)
if(j==0&&k==400)
dp[i][j][k]=0;
else
dp[i][j][k]=oo;
for(i=1;i<=n;i++)
for(j=1;j<=m;j++)
{
for(k=1;k<=800;k++)
if(k>=d[i]-p[i]&&k-d[i]+p[i]<=800)
dp[i][j][k]=max(dp[i-1][j][k],dp[i-1][j-1][k-d[i]+p[i]]+d[i]+p[i]);
}//这就是我的dp方程,,感觉没问题啊,,,就一个01背包,,
int ansk;//下面寻找最佳答案,,
for(k=0;;k++)
{
if(dp[n][m][k+400]>=0&&dp[n][m][k+400]>=dp[n][m][400-k])
{
ansk=400+k;
break;
}
else if(dp[n][m][400-k]>=0)
{
ansk=400-k;
break;
}
}
end=0;
dfs(n,m,ansk);//递归
int px=0,dx=0;
for(i=0;i<end;i++)
px+=p[q[i]],dx+=d[q[i]];//计算,,
printf("Jury #%d\nBest jury has value %d for prosecution and value %d for defence:\n",num++,px,dx);
for(i=end-1;i>=0;i--)
printf(" %d",q[i]);
printf("\n\n");
}
return 0;
}
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