#include<iostream>
#include<algorithm>
using namespace std;
int num[10005];
int main()
{
	int n;
	long long  sum = 0;
	cin>>n;
	for (int i = 0; i < n; i++)
		cin>>num[i];
	sort(num, num + n);
	for (int i = 0; i < n; i++)
		for (int j = i + 1; j < n; j++)
			sum += num[j] - num[i];
	//printf("%d\n", sum * 2);
	cout<<sum * 2<<endl;
	return 0;
}

• Re:Notice~cout就过了，prinf就wa了n遍。。。 (24) conan521 2012-04-19 01:07:38