#include<cstdio>
int main()
{
	int cc,k,a,b,c,d,i;
	scanf("%d",&cc);
	for(k=1;k<=cc;k++)
	{
		scanf("%d%d%d%d",&a,&b,&c,&d);
		printf("Problem set %d: %d / %d, base 7 digits %d through %d: ",k,a,b,c,d);
		a%=b;
		for(i=0;i<=d;i++)
		{
			a*=7;
			if(i>=c)
				printf("%d",a/b);			
			a%=b;
		}
		printf("\n");
	}
	return 0;
}
 

• Re:贴个简短的代码 (398) lnn_rqh 2011-01-13 14:49:17